Thursday, May 15 th : “A” Day Friday, May 16 th : “B” Day Agenda

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Thursday, May 15 th : A Day Friday, May 16 th : B Day Agenda. Collect Crossword Puzzle Collect Concept Review Ch. 15 Review pass back/warm-up Ch. 15 Test Looking Ahead Mon/Tues: Finals Review Wed/Thurs: Fun Lab/Sr. Finals (Thurs) - PowerPoint PPT Presentation

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<ul><li><p>Thursday, May 15th: A DayFriday, May 16th: B DayAgendaCollect Crossword PuzzleCollect Concept ReviewCh. 15 Review pass back/warm-upCh. 15 TestLooking AheadMon/Tues: Finals ReviewWed/Thurs: Fun Lab/Sr. Finals (Thurs) Fri/Tues: Sr. Finals (Fri)/2nd Semester Final Jeopardy</p></li><li><p>Ch. 15 Review/Warm-up#21 Write an equation for the reaction between hydrocyanic acid, HCN, and water. Label the acid, base, conjugate acid and conjugate base.</p><p>HCN + H2O ?HCN + H2O CN- + H3O+</p><p> Acid Base Conjugate Base Conjugate Acid</p></li><li><p>Ch. 15 Review/Warm-up#40 If the hydronium ion concentration of a solution is 1.63 X 10-8 M, what is the hydroxide ion concentration?</p><p>[H3O+] [OH-] = 1.00 X 10-14 M(1.63 X 10-8 M) [OH-] = 1.00 X 10-14 M</p><p>[OH-] = 6.13 X 10-7 M</p></li><li><p>Ch. 15 Review/Warm-up# 47 If [OH-] of an aqueous solution is 0.0134 mol/L, what is the pH?pH = -log [H3O+] </p><p>[H3O+] [OH-] = 1.00 X 10-14 M[H3O+] (0.0134 M) = 1.00 X 10-14 M[H3O+] = 7.46 X 10-13 MpH = -log (7.46 X 10-13 M)pH = 12.1</p></li><li><p>Ch. 15 Review/Warm-up#49 LiOH is a strong base. What is the pH of a 0.082 M LiOH solution?pH = -log [H3O+]LiOH Li+ + OH- 0.082 M 0.082 M[H3O+] [OH-] = 1.00 X 10-14 M[H3O+] (0.082 M) = 1.00 X 10-14 M[H3O+] = 1.2 X 10-13 MpH = -log (1.2 X 10-13 )pH = 13 (2 sig figs)</p></li><li><p>Ch. 15 Review/Warm-up# 63 What is the hydroxide ion concentration in a solution of pH 8.72?</p><p>[H3O+] = 10-pH[H3O+] = 10-8.72[H3O+] = 1.91 X 10-9 M[H3O+] [OH-] = 1.00 X 10-14 M1.91 X 10-9 M [OH-] = 1.00 X 10-14 M</p><p>[OH-] = 5.24 X 10-6 M</p></li><li><p>Ch. 15 Review/Warm-up#78 If 50.00 mL of 1.000 M HI is neutralized by 35.41 mL of KOH, what is the molarity of the KOH?HI + H2O I- + H3O+ 1.000 M 1.000 M(C OH-) (V OH-) = (C H3O+) (V OH-)(C OH-) (0.03541 L) = (1.000 M) (0.05000 L)(C OH-) = 1.412 MKOH K+ + OH- 1.412 M 1.412 M</p></li><li><p>Ch. 15 TestAcids and BasesYou may use your notes, a periodic table, ion charts, and a calculator.</p></li></ul>

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